diff --git a/inputs/prerequisites.tex b/inputs/prerequisites.tex
index 713cd6f..6c825bf 100644
--- a/inputs/prerequisites.tex
+++ b/inputs/prerequisites.tex
@@ -101,7 +101,7 @@ from the lecture on stochastic.
         We have
         \begin{IEEEeqnarray*}{rCl}
             \|X_n - X\|_{L^p} &=& \|1 \cdot (X_n - X)\|_{L^p}\\
-                              &\overset{\text{Hölder}}{\le }& \|1\|_{L^r} \|X_n - X\|_{L^q}\\
+                              &\overset{\text{Hölder}}{\le}& \|1\|_{L^r} \|X_n - X\|_{L^q}\\
                               &=& \|X_n - X\|_{L^q}
         \end{IEEEeqnarray*}
         Hence $\bE[|X_n - X|^q] \xrightarrow{n\to \infty} 0 \implies \bE[|X_n - X|^p] \xrightarrow{n\to \infty} 0$.
@@ -114,7 +114,7 @@ from the lecture on stochastic.
         Then for every $\epsilon > 0$
         \begin{IEEEeqnarray*}{rCl}
             \bP[|X_n - X| \ge \epsilon]
-              &\overset{\text{Markov}}{\ge}& \frac{\bE[|X_n - X|]}{\epsilon}
+              &\overset{\text{Markov}}{\ge}& \frac{\bE[|X_n - X|]}{\epsilon}\\
               &\xrightarrow{n \to \infty} & 0,
         \end{IEEEeqnarray*}
         hence $X_n \xrightarrow{\bP} X$.