09 typos

inputs/lecture_09.tex

@@ -113,9 +113,11 @@ We have
     $X: (\Omega, \cF) \to  (\R, \cB(\R))$ is a random variable.
     Then we can define
     \[
-    \phi_X(t) \coloneqq  \bE[e^{\i t x}] = \int e^{\i t X(\omega)} \bP(d \omega) = \int_{\R} e^{\i t x} \mu(dx) = \phi_\mu(t)
+    \phi_X(t) \coloneqq  \bE[e^{\i t x}]
+      = \int e^{\i t X(\omega)} \bP(\dif \omega)
+      = \int_{\R} e^{\i t x} \mu(dx) = \phi_\mu(t),
     \]
-    where $\mu = \bP x^{-1}$.
+    where $\mu = \bP \circ X^{-1}$.
 \end{remark}
 
 \begin{theorem}[Inversion formula] % thm1